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Home > Archive > Microsoft SQL Server forum > October 2005 > Column By Column Comparison
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Column By Column Comparison
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| csomberg@dwr.com 2005-10-27, 9:24 am |
| SQL Server 2000
I will to compare a normal table with a replicated audit table having
identical columns. I wish to report on the differences between the
data.
How can I loop though a "column list" in TSQL rather than explicitly
naming each column to compare ?
Thanks,
Craig
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| Do you just want to know if there IS a difference or what sort of
difference ?
--For the Whole Table
SELECT checksum_agg(binary_
checksum(*)) from SomeTable
--For just the rows
Select binary_checksum(*) from SomeTable
If you need more granualarity, then it would be more work.
HTH, Jens Suessmeyer.
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| Steve Kass 2005-10-27, 9:24 am |
| Jens,
This is not 100% reliable. If the checksum functions are
different, there must be a difference in the tables, but the
converse is not true. The checksum functions can return the
same values on different data, like any hash function.
The only sure way is to compare column by column values.
Steve Kass
Drew University
Jens wrote:
> Do you just want to know if there IS a difference or what sort of
> difference ?
>
> --For the Whole Table
> SELECT checksum_agg(binary_
checksum(*)) from SomeTable
>
> --For just the rows
> Select binary_checksum(*) from SomeTable
>
> If you need more granualarity, then it would be more work.
>
> HTH, Jens Suessmeyer.
>
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| Yes I agree with you, definitely. But as I said, to have more
granularity and more reliabilty you have to use another mechanism which
causes more coding. but as I said, I am with you.
Jens Suessmeyer.
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| csomberg@dwr.com 2005-10-27, 9:24 am |
| Thanks for the reply.
I have to interrogate each column and determine which is different and
then report on the difference. I was thinking more in the lines of
looping through the columns collection somehow without having to know
the name of each column ...
Thanks again !
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| Erland Sommarskog 2005-10-27, 9:24 am |
| (csomberg@dwr.com) writes:
> SQL Server 2000
>
> I will to compare a normal table with a replicated audit table having
> identical columns. I wish to report on the differences between the
> data.
>
> How can I loop though a "column list" in TSQL rather than explicitly
> naming each column to compare ?
You can get the columns for a table with
SELECT name FROM syscolumns WHERE id = object_name('tbl')
I would suggest that it is best to generate the SQL statement from client
code, since client languages are better apt for string manipulation. You
can build SQL strings in T-SQL as well, and exeute them with EXEC() or
sp_executesql, but this is bulkier.
If you want to be static, one option is to use a client-language to
generate a stored procedure.
Keep in mind that you cannot just say:
SELECT ...
FROM tbl a
JOIN audit_tbl b ON a.keycol = b.keycol
WHERE a.col1 <> b.col1
AND a.col2 <> b.col2
...
Correct is:
WHERE (a.col1 <> b.col1 OR
a.col1 IS NULL AND b.col1 IS NOT NULL OR
a.col1 IS NOT NULL AND b.col1 IS NULL)
AND
--
Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se
Books Online for SQL Server SP3 at
http://www.microsoft.com/sql/techin.../2000/books.asp
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| Hugo Kornelis 2005-10-27, 9:24 am |
| On Fri, 14 Oct 2005 21:51:02 +0000 (UTC), Erland Sommarskog wrote:
(snip)
>Keep in mind that you cannot just say:
>
> SELECT ...
> FROM tbl a
> JOIN audit_tbl b ON a.keycol = b.keycol
> WHERE a.col1 <> b.col1
> AND a.col2 <> b.col2
> ...
>
>Correct is:
>
> WHERE (a.col1 <> b.col1 OR
> a.col1 IS NULL AND b.col1 IS NOT NULL OR
> a.col1 IS NOT NULL AND b.col1 IS NULL)
> AND
Hi Erland,
This can be (slightly) simplified to
WHERE (NULLIF (a.col1, b.col1) IS NOT NULL OR
NULLIF (b.col1, a.col1) IS NOT NULL)
AND
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)
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| Erland Sommarskog 2005-10-27, 9:24 am |
| Hugo Kornelis (hugo@pe_NO_rFact.in_SPAM_fo) writes:
> This can be (slightly) simplified to
>
> WHERE (NULLIF (a.col1, b.col1) IS NOT NULL OR
> NULLIF (b.col1, a.col1) IS NOT NULL)
> AND
Simplified in the sense "few characters to type, yes". Else I'm not
sure that I find it simpler. Or it is just that it's Friday night after
a hard and long working week...
--
Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se
Books Online for SQL Server SP3 at
http://www.microsoft.com/sql/techin.../2000/books.asp
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| Hugo Kornelis 2005-10-27, 9:24 am |
| On Fri, 14 Oct 2005 22:14:32 +0000 (UTC), Erland Sommarskog wrote:
>Hugo Kornelis (hugo@pe_NO_rFact.in_SPAM_fo) writes:
>
>Simplified in the sense "few characters to type, yes". Else I'm not
>sure that I find it simpler. Or it is just that it's Friday night after
>a hard and long working week...
Hi Erland,
Well, okay. It's an acquired taste, I'll have to grant you that. :-)
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)
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| --CELKO-- 2005-10-27, 9:24 am |
|
SELECT X.a, X.b, ... X.z
FROM
(SELECT a, .b, ... z
FROM AuditData
UNION ALL
SELECT a, b, ... z
FROM BaseData)
AS X (a, b, ... z)
GROUP BY X.a, X.b, ... X.z
HAVING COUNT(*) < 2;
or if we had SQL-92 set operators, you could write:
SELECT *
FROM (SELECT 'B', * FROM BaseData)
EXCEPT
(SELECT 'A' , * FROM AuditData);
or
SELECT *
FROM (SELECT 'A', * FROM AuditData)
EXCEPT
(SELECT 'B' , * FROM BaseData);
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| Alexander Kuznetsov 2005-10-27, 9:24 am |
| if the table has a PK, there is no need to do tedios column-by-colmn
comparisons:
create table t1(i int identity, j int)
insert into t1(j) values(1)
insert into t1(j) values(2)
insert into t1(j) values(3)
create table t2(i int identity, j int)
insert into t2(j) values(1)
insert into t2(j) values(2)
insert into t2(j) values(4)
------ rows in t1 that do not have exact match in t2
select * from t1 t
---- there is a row in t2 with the same PK
where exists(select * from t2 where t2.i = t.i)
---- but some other columns are different
and
(select count(*) from
(
select * from t1
union
select * from t2
)t_both where t_both.i = t.i
) = 2
------ rows in t2 that do not have exact match in t1
select * from t2 t
---- there is a row in t1 with the same PK
where exists(select * from t1 where t1.i = t.i)
---- but some other columns are different
and
(select count(*) from
(
select * from t1
union
select * from t2
)t_both where t_both.i = t.i
) = 2
drop table t1
drop table t2
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| csomberg@dwr.com 2005-10-28, 11:23 am |
| Thank you all for the updates and I am sorry I did not get back sooner.
I need to do column bu column comparisons as the "report" has to show
which data elements have changed and from what to what ... yuk.
I do not think I can do this efficiently in SQL so I was thinking of
writing a quick little app to loop through column collections of the
recordset ...
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