PostgreSQL Discussion - getting last day of month

Author

getting last day of month

Sergey Pariev

2005-08-25, 9:24 am

Hi all.
I need to find out the last day of current month. Currently I do the
trick with code below, but that's rather ugly way to do it IMHO. Could
anybody suggest me a better way ?

The following is my testing procedure :

CREATE or REPLACE FUNCTION test_findout_dates()

RETURNS integer AS $$
DECLARE
begin_date date;
end_date date;
current_month int;
current_year int;
last_day int;
BEGIN
current_month := extract ( month from now() ) ;
current_year := extract ( year from now() ) ;

begin_date := current_year || '-' || current_month || '-01' ;

last_day := 31;
begin
end_date := (current_year || '-' || current_month || '-'||
last_day) :: date;
last_day := 0 ;
exception
when others then
raise notice '31 doesnt cut for month %',current_month ;
end;

if last_day > 0 then
begin
last_day := 30;
end_date := (current_year || '-' || current_month || '-'||
last_day) :: date;
last_day := 0 ;
exception
when others then
raise notice '30 doesnt cut for month %',current_month ;
end;
end if;

if last_day > 0 then
begin
last_day := 29;
end_date := (current_year || '-' || current_month || '-'||
last_day) :: date;
last_day := 0 ;
exception
when others then
raise notice '29 doesnt cut for month %',current_month ;
end;
end if;

if last_day > 0 then
begin
last_day := 28;
end_date := (current_year || '-' || current_month || '-'||
last_day ) :: date;
last_day := 0 ;
exception
when others then
raise notice '28 doesnt cut for month %',current_month ;

end;
end if;

raise notice 'begin date is % ',begin_date;
raise notice 'end date is % ',end_date;

return 1;
END;
$$ LANGUAGE plpgsql ;

Thans in Advance, Sergey.

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Sergey Moiseev

2005-08-25, 9:24 am

Sergey Pariev wrote:
> Hi all.
> I need to find out the last day of current month. Currently I do the
> trick with code below, but that's rather ugly way to do it IMHO. Could
> anybody suggest me a better way ?
select '2005-09-01'::date-'1 day'::interval does the trick :)
--
Wbr, Sergey Moiseev

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josue

2005-08-25, 9:24 am

Sergey,

Try this one:

CREATE OR REPLACE FUNCTION public. lastdayofmonth(date)

RETURNS date AS
'

select ((date_trunc('month
', $1) + interval '1 month') - interval
'1 day')::date;

'
LANGUAGE 'sql' VOLATILE;

Sergey Pariev wrote:
> Hi all.
> I need to find out the last day of current month. Currently I do the
> trick with code below, but that's rather ugly way to do it IMHO. Could
> anybody suggest me a better way ?
>
> The following is my testing procedure :
>
> CREATE or REPLACE FUNCTION test_findout_dates()

> RETURNS integer AS $$
> DECLARE
> begin_date date;
> end_date date;
> current_month int;
> current_year int;
> last_day int;
> BEGIN
> current_month := extract ( month from now() ) ;
> current_year := extract ( year from now() ) ;
>
> begin_date := current_year || '-' || current_month || '-01' ;
>
> last_day := 31;
> begin
> end_date := (current_year || '-' || current_month || '-'||
> last_day) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '31 doesnt cut for month %',current_month ;
> end;
>
> if last_day > 0 then
> begin
> last_day := 30;
> end_date := (current_year || '-' || current_month || '-'||
> last_day) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '30 doesnt cut for month %',current_month ;
> end;
> end if;
>
> if last_day > 0 then
> begin
> last_day := 29;
> end_date := (current_year || '-' || current_month || '-'||
> last_day) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '29 doesnt cut for month %',current_month ;
> end;
> end if;
>
> if last_day > 0 then
> begin
> last_day := 28;
> end_date := (current_year || '-' || current_month || '-'||
> last_day ) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '28 doesnt cut for month %',current_month ;
>
> end;
> end if;
>
> raise notice 'begin date is % ',begin_date;
> raise notice 'end date is % ',end_date;
>
> return 1;
> END;
> $$ LANGUAGE plpgsql ;
>
> Thans in Advance, Sergey.
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 6: explain analyze is your friend
>
>

--
Sinceramente,
Josué Maldonado.

.... "Monogamia: ilusión falaz de establecer relaciones con una pareja a
la vez."

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Tino Wildenhain

2005-08-25, 9:24 am

Sergey Pariev schrieb:
> Hi all.
> I need to find out the last day of current month. Currently I do the
> trick with code below, but that's rather ugly way to do it IMHO. Could
> anybody suggest me a better way ?
>
> The following is my testing procedure :
>
> CREATE or REPLACE FUNCTION test_findout_dates()

> RETURNS integer AS $$
> DECLARE
> begin_date date;
> end_date date;
> current_month int;
> current_year int;
> last_day int;
> BEGIN
> current_month := extract ( month from now() ) ;
> current_year := extract ( year from now() ) ;
>
> begin_date := current_year || '-' || current_month || '-01' ;
>
> last_day := 31;
> begin
> end_date := (current_year || '-' || current_month || '-'||
> last_day) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '31 doesnt cut for month %',current_month ;
> end;
>
> if last_day > 0 then
> begin
> last_day := 30;
> end_date := (current_year || '-' || current_month || '-'||
> last_day) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '30 doesnt cut for month %',current_month ;
> end;
> end if;
>
> if last_day > 0 then
> begin
> last_day := 29;
> end_date := (current_year || '-' || current_month || '-'||
> last_day) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '29 doesnt cut for month %',current_month ;
> end;
> end if;
>
> if last_day > 0 then
> begin
> last_day := 28;
> end_date := (current_year || '-' || current_month || '-'||
> last_day ) :: date;
> last_day := 0 ;
> exception
> when others then
> raise notice '28 doesnt cut for month %',current_month ;
>
> end;
> end if;
>
> raise notice 'begin date is % ',begin_date;
> raise notice 'end date is % ',end_date;
>
> return 1;
> END;
> $$ LANGUAGE plpgsql ;
>
> Thans in Advance, Sergey.

SELECT date_trunc('month',C
URRENT_DATE) + interval '1 month' - interval
'1 day';

HTH
Tino Wildenhain

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match

Patrick.FICHE@AQSACOM.COM

2005-08-25, 9:24 am

You could try :

SELECT int4(EXTRACT( DAYS FROM CURRENT_DATE + '1 month'::interval -
CURRENT_DATE ));

----------------------------------------------------------------------------
---------------
Patrick Fiche
email : patrick.fiche@aqsacom.com
tel : 01 69 29 36 18
----------------------------------------------------------------------------
---------------

-----Original Message-----
From: pgsql-general-owner@postgresql.org
[mailto:pgsql-general-owner@postgresql.org]On Behalf Of Sergey Pariev
Sent: jeudi 25 aout 2005 18:44
To: pgsql-general postgresql.org
Subject: [GENERAL] getting last day of month

Hi all.
I need to find out the last day of current month. Currently I do the
trick with code below, but that's rather ugly way to do it IMHO. Could
anybody suggest me a better way ?

The following is my testing procedure :

CREATE or REPLACE FUNCTION test_findout_dates()

RETURNS integer AS $$
DECLARE
begin_date date;
end_date date;
current_month int;
current_year int;
last_day int;
BEGIN
current_month := extract ( month from now() ) ;
current_year := extract ( year from now() ) ;

begin_date := current_year || '-' || current_month || '-01' ;

last_day := 31;
begin
end_date := (current_year || '-' || current_month || '-'||
last_day) :: date;
last_day := 0 ;
exception
when others then
raise notice '31 doesnt cut for month %',current_month ;
end;

if last_day > 0 then
begin
last_day := 30;
end_date := (current_year || '-' || current_month || '-'||
last_day) :: date;
last_day := 0 ;
exception
when others then
raise notice '30 doesnt cut for month %',current_month ;
end;
end if;

if last_day > 0 then
begin
last_day := 29;
end_date := (current_year || '-' || current_month || '-'||
last_day) :: date;
last_day := 0 ;
exception
when others then
raise notice '29 doesnt cut for month %',current_month ;
end;
end if;

if last_day > 0 then
begin
last_day := 28;
end_date := (current_year || '-' || current_month || '-'||
last_day ) :: date;
last_day := 0 ;
exception
when others then
raise notice '28 doesnt cut for month %',current_month ;

end;
end if;

raise notice 'begin date is % ',begin_date;
raise notice 'end date is % ',end_date;

return 1;
END;
$$ LANGUAGE plpgsql ;

Thans in Advance, Sergey.

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TIP 6: explain analyze is your friend

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Chris Browne

2005-08-25, 8:24 pm

egy@tnet.dp.ua (Sergey Pariev) writes:
> I need to find out the last day of current month. Currently I do the
> trick with code below, but that's rather ugly way to do it IMHO. Could
> anybody suggest me a better way ?

log_analysis=# select date_trunc('months',
(date_trunc('months'
, now()) + '45 days'::interval)) - '1 day'::interval;
?column?
------------------------
2005-08-31 00:00:00+00
(1 row)

So...

log_analysis=# create or replace function eom (timestamptz) returns timestamptz as '
log_analysis'# select date_trunc(''months'
', (date_trunc(''months
'', $1) + ''45 days''::interval)) - ''1 day''::interval;' language sql;
CREATE FUNCTION
log_analysis=# select eom(now());
eom
------------------------
2005-08-31 00:00:00+00
(1 row)
log_analysis=# select eom('2004-07-02');
eom
------------------------
2004-07-31 00:00:00+00
(1 row)

log_analysis=# select eom('2004-02-29');
eom
------------------------
2004-02-29 00:00:00+00
(1 row)
log_analysis=# select eom('2004-02-29'), eom('2005-02-28'), eom('2005-03-01');
eom | eom | eom
------------------------+------------------------+------------------------
2004-02-29 00:00:00+00 | 2005-02-28 00:00:00+00 | 2005-03-31 00:00:00+00
(1 row)
--
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