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Home > Archive > Pgadmin > June 2005 > Question about creating a new server
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Question about creating a new server
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| Danny Gaethofs 2005-06-15, 8:25 pm |
| Dear all,
Running postgresql 8.0 on windows xp.
I tried to create a second server from within
pgadminiii.
address = localhost
Service = pgsql-8.0
user = postgres
port = 5433
When I do so I get the error message
error connecting to the server: could not connect to
server: connection refused (.....)
Is the server running on host '127.............
and accepting tcp/ip connection on port 5433
Can anyone explain me why it is not possible to create
a new server?
If I would create a new server using initdb would it
then become visible in pgadminiii?
regards,
Danny
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| Diego Gil 2005-06-15, 8:25 pm |
| Hi,
I suppose you mean a "second server connection". Do you have a working
connection ?.
I don't work in Windows but these topic is a recurring one in this list.
Maybe is a firewall preventing you to connect, but it doesn't make
sense is there is a actual working connection.
It is obvious, but are you sure postgresql is running ?.
Diego.
El mié, 15-06-2005 a las 09:59 -0700, Danny Gaethofs escribió:
> Dear all,
>
> Running postgresql 8.0 on windows xp.
>
> I tried to create a second server from within
> pgadminiii.
>
> address = localhost
> Service = pgsql-8.0
> user = postgres
> port = 5433
>
> When I do so I get the error message
> error connecting to the server: could not connect to
> server: connection refused (.....)
> Is the server running on host '127.............
> and accepting tcp/ip connection on port 5433
>
> Can anyone explain me why it is not possible to create
> a new server?
>
> If I would create a new server using initdb would it
> then become visible in pgadminiii?
>
> regards,
> Danny
>
>
>
> ____________________
______________
> Discover Yahoo!
> Get on-the-go sports scores, stock quotes, news and more. Check it out!
> http://discover.yahoo.com/mobile.html
>
> ---------------------------(end of broadcast)---------------------------
> TIP 9: the planner will ignore your desire to choose an index scan if your
> joining column's datatypes do not match
>
>
---------------------------(end of broadcast)---------------------------
TIP 5: Have you checked our extensive FAQ?
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