Drop Table
Support Forum for database administrators and web based access to important newsgroups related to databasesI am working with the RTM Standard Edition of SQL Server 2005 and Deadlock
trace output is not getting written to the error log. I use the -T startup
parameter and specify -T1204; -T 3605. I set the startup parameters using
the SQL Server 2005 Configuration Manager. I then restart the SQL Server
service and create a deadlock. The deadlock info. is not written to the
error log.
If I run the DBCC TRACEON (1204, 3605, -1) then the output appears in the
error log.
I also tried the low case ("-t") startup option and it did not work. As a
last ditch effort, I set the -T 1222 startup parameter but once again the
trace output is not written to the error log.
This seems to be a bug.
Please help.
Thanks!
Chris
Post Follow-up to this messageAre you 100% certain you specify the startup parameters for the correct inst ance? I just added the flag and I did indeed get a dump in the errorlog for my deadlock. Btw, Profi ler has a nice graphical deadlock viewer in 2005. -- Tibor Karaszi, SQL Server MVP http://www.karaszi.com/sqlserver/default.asp http://www. solidqualitylearning .com/ Blog: http:// solidqualitylearning .com/blogs/tibor/ "Cgal" < cgallelli@newsgroups .nospam> wrote in message news:%23mqLZ98OGHA.4052@TK2MSFTNGP15.phx.gbl... >I am working with the RTM Standard Edition of SQL Server 2005 and Deadlock trace output is not >getting written to the error log. I use the -T startup parameter and speci fy -T1204; -T 3605. I >set the startup parameters using the SQL Server 2005 Configuration Manager. I then restart the SQL >Server service and create a deadlock. The deadlock info. is not written to the error log. > > If I run the DBCC TRACEON (1204, 3605, -1) then the output appears in the error log. > > I also tried the low case ("-t") startup option and it did not work. As a last ditch effort, I > set the -T 1222 startup parameter but once again the trace output is not w ritten to the error log. > > This seems to be a bug. > > Please help. > > Thanks! > > Chris >
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