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Scheduled job hangs the server
Sorry re-posted as my email setting were wrong on the last post



I wonder if anyone can help.

I have a scheduled job running overnight to delete old records for a
particular Db table.

The table contains more than half million records and the script
simply uses the date field to delete any of the records which have a
date older than 7 days. My guess is that there will be some 100,000
records which need to be deleted.

The job takes ages to run and whilst it is running sql server is
completely locked and the associated website is effectively offline
because of it.

I think I know where the problem lies but I don't know why.

Whoever created the Db table created a varchar 255 field as the
primary key. The field is then filled with a string of 40 characters
generated within the webserver script to have a 'unique' string.

Those are the facts. The following is my interpretation.

I think the server is unable to cope with not only a character field
as primary key but also one with so many characters in it. In such a
larger table presumably in order to delete the old records it must do
some sort of ordered sort on the Primary Key and it is this that is
causing the problem.

I would like to introduce a new field called 'id' make it autonumbered
and primary and make the errant field non-primary.

So my question is this:

Is my analysis correct but more importantly, why? Can anyone give me
clear reasoning for it.

Also is the solution sound?


Table looks like this:

clientID int
refID varchar 255 Primary Key
fieldA varchar 512
creationDate datetime
fieldB varchar 255
field C varchar 32

Job script:

delete from myTable where creationDate < [7daysAgo]



Thanks in anticipation

Bill

Report this thread to moderator Post Follow-up to this message
Old Post
Bill
11-20-05 12:23 PM


Re: Scheduled job hangs the server
Bill (wje@blueyonder.co.uk)  writes:
> The table contains more than half million records and the script
> simply uses the date field to delete any of the records which have a
> date older than 7 days. My guess is that there will be some 100,000
> records which need to be deleted.
>
> The job takes ages to run and whilst it is running sql server is
> completely locked and the associated website is effectively offline
> because of it.

I doubt that SQL Server is completely locked. You shoudl be able to
log in and to an sp_who.

But if the table is essential for the function of the web site, I can
understand that the table is entire inaccessible during this time.

Furthermore, if there are other tables referencing this table through
foreign-key constraints, and those tables are huge and the FK columns
are non-indexed, this can be a really aggrevating factor. In the below
I don't discuss this further (as this occurred to me as I was about to
post), but you must definitely investigate it.

> Whoever created the Db table created a varchar 255 field as the
> primary key. The field is then filled with a string of 40 characters
> generated within the webserver script to have a 'unique' string.
>...
> I think the server is unable to cope with not only a character field
> as primary key but also one with so many characters in it. In such a
> larger table presumably in order to delete the old records it must do
> some sort of ordered sort on the Primary Key and it is this that is
> causing the problem.

That is not likely. However, if the clustered index is not on the date
field, SQL Server will have to scan the entire table. Furthermore, if
the PK is clustered, and its values are random, the deletion will cause
gaps and leave the table fragmented as Stu points out. Then again, if
the PK is indeed clustered, then new rows should fall in the gaps,
so the fragmentation would be reduced as new rows appear. Yet, then
again, if that generated string is not entirely random, it may be more
complicated.

You can examine fragmentation with DBCC SHOWCONTIG. The cure for
fragmentation is to run DBREINDEX.

> I would like to introduce a new field called 'id' make it autonumbered
> and primary and make the errant field non-primary.
>
> So my question is this:
>
> Is my analysis correct but more importantly, why? Can anyone give me
> clear reasoning for it.
>
> Also is the solution sound?

No, the solution will not solve all your problems. First of all, PK does
not matter here - what matters is where you have the clustered index on
the table. If you add an autonumber column and add a clustered index on
that column (PK or not), you will not see fragementation, assuming that
the date column is fully correlated with the autonumber. But the DELETE
operation will still lock the table.

There are two ways to go:
1) Add an autonumber column with a clustered index on it, and then change
the job, so that it looks up the newest row to delete:

SELECT @id = MIN(id) FROM tbl WHERE datecol < @deletedate

And then use @id for deleting the rows. You would need a non-clustered
index on datecol for this be optimal.

2) Make the PK non-clustered and add a clustered index on the date column.

I would recommend the latter, unless you know that the current clustered
index is very good for something else.

The point with aligning the DELETE with the clustered index, is that
then the DELETE operation does not have to lock the entire table, only
the rows to be deleted.

By the way, just adding a non-clustered index on the date column is not
likely to help with the numbers you've indicated. If 20% of the rows are
hit by the condition, SQL Server is not going to use that index anyway.

--
Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pr...oads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodin...ions/books.mspx

Report this thread to moderator Post Follow-up to this message
Old Post
Erland Sommarskog
11-21-05 01:23 AM


Re: Scheduled job hangs the server
Sorry it's taken a while for me to respond Erland.

When I get time I'm going to chose your option 2. I've been doing a
bit of reading and now understand the problem much better.

Thank you for taking the time to respond it is very much appreciated.
Once the correction is made I shall let you know how successful it has
been.

Thanks

Bill



On Sun, 20 Nov 2005 19:27:14 +0000 (UTC), Erland Sommarskog
<esquel@sommarskog.se> wrote:

>Bill (wje@blueyonder.co.uk) writes: 
>
>I doubt that SQL Server is completely locked. You shoudl be able to
>log in and to an sp_who.
>
>But if the table is essential for the function of the web site, I can
>understand that the table is entire inaccessible during this time.
>
>Furthermore, if there are other tables referencing this table through
>foreign-key constraints, and those tables are huge and the FK columns
>are non-indexed, this can be a really aggrevating factor. In the below
>I don't discuss this further (as this occurred to me as I was about to
>post), but you must definitely investigate it.
> 
>
>That is not likely. However, if the clustered index is not on the date
>field, SQL Server will have to scan the entire table. Furthermore, if
>the PK is clustered, and its values are random, the deletion will cause
>gaps and leave the table fragmented as Stu points out. Then again, if
>the PK is indeed clustered, then new rows should fall in the gaps,
>so the fragmentation would be reduced as new rows appear. Yet, then
>again, if that generated string is not entirely random, it may be more
>complicated.
>
>You can examine fragmentation with DBCC SHOWCONTIG. The cure for
>fragmentation is to run DBREINDEX.
> 
>
>No, the solution will not solve all your problems. First of all, PK does
>not matter here - what matters is where you have the clustered index on
>the table. If you add an autonumber column and add a clustered index on
>that column (PK or not), you will not see fragementation, assuming that
>the date column is fully correlated with the autonumber. But the DELETE
>operation will still lock the table.
>
>There are two ways to go:
>1) Add an autonumber column with a clustered index on it, and then change
>   the job, so that it looks up the newest row to delete:
>
>    SELECT @id = MIN(id) FROM tbl WHERE datecol < @deletedate
>
>   And then use @id for deleting the rows. You would need a non-clustered
>   index on datecol for this be optimal.
>
>2) Make the PK non-clustered and add a clustered index on the date column.
>
>I would recommend the latter, unless you know that the current clustered
>index is very good for something else.
>
>The point with aligning the DELETE with the clustered index, is that
>then the DELETE operation does not have to lock the entire table, only
>the rows to be deleted.
>
>By the way, just adding a non-clustered index on the date column is not
>likely to help with the numbers you've indicated. If 20% of the rows are
>hit by the condition, SQL Server is not going to use that index anyway.


Report this thread to moderator Post Follow-up to this message
Old Post
Bill
11-25-05 01:23 AM


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